1. In
the given figure,the number of node and branch in the circuit are respectively
2. In the given Circuit the value of the voltage source E is
All possible number of trees of a graph corresponding to given reduced incidence matrix is
7.The Power supplied by 5A source in the Circuit is
A. 1,5,3,9
13.After Keeping it open for a long time ,the Switch 'S' in the circuit shown in the given figure is closed at t=0. The capacitor Voltage Vc ( 0+) and inductor current iL(0+) will be
A.
n= 2, b= 3
B. n= 3, b= 4
C.
n= 4, b= 5
D. n=6 ,b = 5
2. In the given Circuit the value of the voltage source E is
B. 4v
C. -6v
D. 16v
3.In
the given Circuit, which of the elements of the circuit have their current
Direction and voltage polarity in the proper relationship for positive power
absorbed by the element?
A. C,D,E
B.
A,B,E
C.
A,B
D. C,D
4.
In the given figure ,Identify Which of the following is not a tree of the graph
A. bcgh
B. defg
C. abfg
D.
argh
5.The
Reduced incidence matrix of a graph is given by
All possible number of trees of a graph corresponding to given reduced incidence matrix is
A. 10
B. 12
C. 16
D. 20
6. If R1= R2=R4= R and R3= 1.1 R in the
bridge circuit shown in figure ,then the reading in the ideal voltmeter
connected between a and b is
A. 0.238V
B. 0.138V
C. -0.238V
D. 1V
7.The Power supplied by 5A source in the Circuit is
A. 15.5
W
B.
20.5W
C.
17.5W
D.
25.5W
8.The Maximum power that can be transferred
to the load resistor RL from the voltage source in figure is
A. 1W
B. 10W
C. 0.25W
D. 0.5W
9. A Delta – connected network with its Wye-
equivalent is shown in figure .The resistance R1,R2,and R3 (in ohms)are
respectively
A. 1,5,3,9
B. 3,9,1.5
C. 9,3,1.5
D. 3,1.5,9
10.In the Circuit shown below,the current
through the inductor is
A. 2/ 1+ jA
B. -1/1+j
A
C. 1/
1+j A
D. 0
11.The Thevenin's equivalent (Rth and Vth
respectively ) of the following Circuit is
A. 16Ohm ,5V
B.
8Ohm ,2.5V
C. 5Ohm,16V
D. 2.5Ohm
,8V
12.The Norton’s equivalent ( Rth and Isc
respectively ) with respect to terminal
a-b are
For the circuit given
Vo= 2V, R1= 2.5kOhm ,R2= 5kOhm ,C= 100
A. 5KOhm ,80mA
B. 10KOhm
,160mA
C. 5KOhm
,-80 mA
D. 10KOhm
,-160mA
13.After Keeping it open for a long time ,the Switch 'S' in the circuit shown in the given figure is closed at t=0. The capacitor Voltage Vc ( 0+) and inductor current iL(0+) will be
A. 60V and -0.3A
B. 150V and zero
C. 60V
and 0.3A
D. 90V and -0.3A
14.The
switch in the circuit shown was on position a for along time ,and is moved to
position b at time t=0 .The current i(t) for t> 0 is given by
A. 0.2e^-125t u(t) mA
B. 20e^-1250t u(t) mA
C. 0.2e^-1250t u(t)mA
D.20e^-1000t u(t) m
15.Steady state is reached with S open .S is
closed at t= 0,i(t) for t>0 is given by
A. 6-4e^
-3t A
B.
6-4e^-t A
C. 6-
3e^-t A
D. 6-6
e-3t A
16.A series RLC circuit has R= 80 ohm ,L=
240mH and C= 5mF.lf the input Voltage is V(t)= 10cos 2t V then current flowing
through the Circuit is
A. 29.61cos ( 2t-51.2°)mA
B. 29.61cos ( 2t+51.2°) mA
C. 78.32cos ( 2t-51.2° ) mA
D. 78.32cos (2t+ 51.2°)mA
17.The network is as shown in figure.If R1=
1kOhm, R2= 1kOhm,C= 6.363uf and
Is= 100<60° A then V2 is
A. 29.21×10^3<60°
V
B. 15.52×10^3<-21°V
C. 15.52×10^3<60°
V
D. 29.21×
10^3<-21° V
18. Laplace transform of an capacitor is as
shown in figure.The initial voltage Vc(0) is
A. 2V
B.2.5V
C.3V
D.3.5V
19. A series RLC circuit has resonance frequency
of 1khz and a quality factor
A. 25
B. 50
C. 100
D. 200
20. Given transfer function of band pass
filter
H(s)
= s/ s^2 + 24s +36
The
frequency at which |H(w)|is maximum is
A. 6
rad /sec
B. 12rad/sec
C. 18rad/sec
D. 24rad/sec